Let f:R-->R be a continuous function such that f(x)-2f(x2)+f(x4) = x2.
f(3) is equal to
(A) f(0) (B) 4+f(0) (C) 9+f(0) (D) 16+f(0).
The equation f(x)-x-f(0) = 0 has exactly
(A) No solution (B) One solution (C) Two solutions (D) Infinite solutions.
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3 Answers
Soumyadeep Basu
·2013-06-29 08:54:19
Anyone??!!
- Sourup Nag yes please.... Upvote·0· Reply ·2013-06-29 09:53:29
- Prodipta Bose eta ekhono parini
Jeet Sen Sharma
·2013-06-29 11:57:15
Replace x by x/2..... do it for n times... and add them... :)
- Jeet Sen Sharma then tend x to infinity, to get a eqation of f(x)
- Jeet Sen Sharma actually i am stuck after this.... its coming somthing like, f(x)-f(x/2)= (4x^2)/3 then.... !!!
- Sourish Ghosh Jeet, do the same thing after this also, put x = x/2. You'll get f(x) - f(x/4n) = something