2.
replace x by 1/x
u get
2f(1/x2)+3f(x2)=1-x2/x2----(2)
2f(x2)+3f(1/x2)=x2-1-----(1)
Multiplying (1) by 3 and (2) by 2 and subtracting both the equations u arrive at ur answer!
1. f(x)= sin-1 (sin x)...find its period....
2. 2f(x2) + 3f(1/x2) = x2 -1......for all x belonging to R - {0} then f(x2) = ?????
pls ans urgently required...!!!!
2.
replace x by 1/x
u get
2f(1/x2)+3f(x2)=1-x2/x2----(2)
2f(x2)+3f(1/x2)=x2-1-----(1)
Multiplying (1) by 3 and (2) by 2 and subtracting both the equations u arrive at ur answer!
sin-1sinx is periodic with a period of 2∩
sin-1(sinx) =x [-∩/2,∩/2]
= ∩-x [∩/2,3∩/2]
so its graph will be