1my ans comes out to be b
but the ans is a
If f: R →[Π/6, Π/2), f(x) = sin-1 (x2-a)/(x2+a) is a onto funtion, then set of values of 'a' is:
a. {-1/2}
b. [-1/2. -1)
c. [1/2. -1)
d. {1/2}
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5 Answers
11we here observe that
\frac{1}{2}\leq \frac{x^{2}-a}{x^{2}+a}<1
we get
x^{2}>3a
and
2a>0
I am getting D
11how come u know the answer[11]
if i am wrong then
PLEASE PROVE IT
1ans just cant be a.
it would give arcsin(.) of a value which is greater than 1.
