the correct answer is -1/9!!!!!!!!!!!!!
if primitive of t2dt from 0 to any f(x) is xcosx, then find f'(9)!!!!!!!!!
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3 Answers
satan92
·2008-12-04 20:09:38
integrating we see that
f(x)3/3=xcosx
hence f(x)=(3xcosx)1/3
form here we get f'(x) and the asnwer comes out to be
[cos9-9sin9]/(27cos9)2/3