71I tried hard and then gave up. Please see this :
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By Mathematica.
There might however exist some method. I'm trying that one. Will post if I get it.
EDIT: No it doesn't works!
\hspace{-16}\mathbf{\int\frac{x.\sin^2 x}{\cos (2x).\cos^2 x}dx}
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6 Answers
71
39can anyone give the integration of 1/cos2xcos2x ?
then the sum is done
39well then if thats not easy to evaluate then this is one nasty integral or we need to come up with some kickass substitution which i guess all of us would have tried
so unless we do something about the integral i have said, as far as i have checke dout there is no other way out
anyone gng anywhere with that?
71No.. Now people don't waste too much time on it now. It's JEE time. So go to next.