plz solve this!!!!!!!!
7 Answers
monkeyman
·2009-08-16 02:21:10
dude its a standard integral of the form x^2 - a^2 where a is constant
in your case a=1 and x^16=x^2^8
Dr.House
·2009-08-16 02:32:01
monkey man,
i am really waiting to see how you would do the way u said. can u post full solution.
Debotosh..
·2009-08-19 10:50:11
monkey....really the name suggests that.....look at (dx)....for the way you are suggesting it should have been d(x8) because x16 = ( x8)2
Mani Pal Singh
·2009-08-19 12:33:03
@sum
write it as ∫tan@√tan@d@
put tan@=t and sec^2 @ d@=dt and also sec^2 @ =1+tan^2 @
use both and get ur answer
and vimalesh
u need ∫1x^16-1dx
so put x=sec1/8@ dx=1/8 sec-7/8d@
ab kya reh gaya iss mein
solve it
time lagega :|