1Bhai SR , can you integrate , dx√1 - x4
limits being from 0 to 1 ?
1. \int \frac{x^2}{\sqrt{1- x^2}}
2. \int \frac{x^3}{\sqrt{1- x^2}}
3 . \int \frac{dx}{( x^2 + 1 ) ^2 } = \frac{A}{148}\tan^{-1} x +\frac{x}{2(x^2 + 1)}
find value of A
4 .\int \frac{(1+ logx )dx}{\sqrt{x^{2x}-1}}
for practice
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34 Answers
1@QWERTY ehhh!
i know who gave u that link.....
but i dont like someone copy pasting from somewer and then claming it to be his soln..
not a smart work indeed ?
1accha
i know who gav it to u [6]
dont lie [3]
btw if i post something its quiet obvious that the thing is posted by me and not a
copied one
if u copy better post the sorce also.
1yaar first wale ke liye itna jhamela kyun mar rahe ho plain separation of terms se 2 step mein answer aa jayega[1]
1may i know why teh hell people here delete der posts days after posting them....?
this is jus not a good thing....
i dun know why der is no time limit on this site after which posts cant be deleted by the user......
1I DUNNO WHY PEOPLE FIGHT HERE
BUT ONE TGIITIAN HERE SAY'STHAT OTHERS ARE COPYIN
AND IN THE MEANWHILE
FORGET TO SAY'S
THE SOURCE FROM WHERE HE COPIED THE ANSWERS,
HINTS ETC
I THINK
SAMAJHNE WAALE KO ISHAARA KAAFI HAI
1LoL @ omkar satish prabhu
Jus shut ur bloody mouth up.
And btw wat du u mean by that ?
Der r hundreds of q asked here…and almost I mean almost will be in some or the oder book…now does that mean that the one who answers has flitched his soln from book…lol
And btw I said to qwery becuz that was the exact copy paste…I mean each and every word ….ditto..thats why I said and I don’t hav arihant books with me…
So better shut ur mouth up wen u don’ know anethying.. and then read my signature[3] ..easpecially for u..[3]
1hey
i don want to argue with any one
and ur signature
u will do it at ur pleasure ....!!!!
teri ggandi zabaan ko lagaam de
warna muje lagaam dena sikhaana padega
tu chup rah jaa!!!
aur tera ye attitude tere , family aur friends ke saath dikha
hamaare jaise logon se nahii \
tu apne aap copy karta hai
aur dusron ko copycat bolta haii
ur the biggset plagariastic person
tera signature se teri gaandi dimaag ki gandi cheezein saaf kulkar
dikthi hain
do chaar bol lega lol kahega gaali dega , itne karne ke baat kya
mein chup baita rahoon ye hi socha hoga tumene
tumhare jaise gande aadmiyon ko kyaa aata hai siwaay kisi ko gaali
dene ke bajaay
itna selfish hai too ki
kehke kuch faida nahin
1not oders copy but u flitch solutions
since ur a plagiaristic person !!!!
a war shud be 2 sided hence let us finish war here at targetiit
since this a forum for integration
i will mail my e-mail adress at both of ur gmail -ids
so aali dena hai to seedha mere inbox mein not here
HOPE IT IS CLEAR
1Oh god....jus look at the way this guy talks......Now seriously this is all getting above head....seriously if u hav any issues with me Mr omkar then give ur email id....i will give u a good dose of all ur supposedly ""GALLIS" which ur talking about.....How can a person degrade to such a level of CHEAP talking as u r doing Mr omkar....and were teh hell did i abuse u....let me tell u ..i dont like taking to d**s..who jus bark and cant do anything in life :P and i was talking to qwerty not To u....didya get that....why the hell u jumped in between....
and those who dont know abt thius guy let me tell u ....this guy was in goiit ....always fighting and abusing with everyone there....he is a history sheeter in this case....so tats why he was thrown out of there now he has come here to disturb everybody
if u dont belivve see these
http://www.goiit.com/posts/list/about-iits-and-jee-see-what-terrible-language-our-very-own-user-992946.htm
http://www.goiit.com/posts/list/integral-calculus-this-omkar-satish-is-pissing-me-off-u-tell-996062.htm
therre r more i can show u....but i dont want to stretch this issue....
11@ Gallardo, I think that's not integrable....It seems to be coming in terms of beta functions....Anyways I didn't try it now, it actually resembls a qsn exactly - a qsn that eure posted months back here.
1@SR thats no easy
as said by soumik
it invovles some thing "complex"
i checked mathematica
1Soumik is absolutely correct , the answer wil come in terms of Beta funtions . Interestingly , the answer of that definite integral multiplied by 2 / pi gives Gauss's constant , which again , interestingly , is reciprocal of the arithmatic- geometric mean between 1 and root 2.
62@everyone.. why are u all behaving like kids.. grow up
Yes one should always give reference to where somethign has been copied from...
Another thing is that if some person abuses someone else and you abuse back then what is the difference b/w the two of you..
either kick him so hard that he never abuses back or just ignore :D
1ANS
1 . \frac{1}{2} \left(\sin^{-1} x + x\sqrt{1-x^2} \right)+c
2.
-\sqrt{1-x^2} +\frac{\left(1- x^2 \right)^{\frac{3}{2}}}{3}+c
3. 74
4. sec^{-1}(x^{x}) + c
29Omkar these integrations seem easy...
1..Put x = sinθ
2..put 1-x2 = t2 ...
1@ great dreams it is shorter method than evaluating ∫sin^3θ
1two methods done for 1
still one( or more ) method remaining !!!!
typo in answer for 1st ques there is minus sign in between
12.
expand the terms and use sum and differences formulae u get it as
\sqrt{ 3 + cos 3x + cosx + cos 5x + cosx + cos 4x + cos2x + cosx -cos3x + cosx - cos5x + cos2x -cos4x }
\sqrt{ 3 + 2cos2x + 4cosx }
\sqrt{ 3 + 2( 2cos^2x -1 ) + 4cosx } = \sqrt{3+ 4cos^2x -2 + 4cosx }
\sqrt{ 4cos^2x + 4cosx + 1 }
\sqrt{( 2cosx + 1 )^2 } = 2cosx + 1
integral reduces to
\int_{0}^{\pi}{} 2cosx + 1 dx = \pi