rearranging we get
(x+1)(2-y)=2
so the left wo terms can be
2,1
-1,-2
1,2
-2,-1
hence the solutions are
(1,1)
(-2,4)
(0,0)
(-3,3)
solve fr x and y
xy=2x-y solve for x and y. x and y are integers
rearranging we get
(x+1)(2-y)=2
so the left wo terms can be
2,1
-1,-2
1,2
-2,-1
hence the solutions are
(1,1)
(-2,4)
(0,0)
(-3,3)
It is evident that x|y
Hence y = kx
Hence we get kx2 = 2x-kx
Noting that (0,0) is a solutio, divide by kx to get
x = 2/k - 1
Thus k = ±1 or ±2
and x=0,1,-2,-3