If f(x) and φ(x) are continuous function in[0,4] satisfying f(x)=f(4-x),φ(x) + φ(4-x)=3 and ∫40f(x)dx=2,then the value of ∫40 f(x)φ(x)dx is:
NOTE:The upper and lower limits are 4 and 0
-
UP 0 DOWN 0 0 1
1 Answers
Manish Shankar
·Jul 15 at 1:05
I=∫04f(x)φ(x)dx=∫04f(4−x)φ(4−x)dx=∫04f(x)(3−φ(x))dx=∫04(3f(x)−f(x)φ(x))dx
Sushovan Halder thanks sir
Upvote·0· Reply ·Jul 15 at 5:32