1using prop. of defnt integral,
a=\int_{0}^{1}{e^{1-t}/(2-t)}
similarly ,B=\int_{3}^{4}{e^{7-t}/(2-t)}
so,a/b=1/e^{6}
i know this is not directly integrable, bt i'm nt getting any way to directly derive this relationship
if\int_{0}^{1}{\frac{e^{t}}{t+1}} =a
and\int_{3}^{4}{\frac{e^{t}}{t-5}} =b
then find the relation btw a and b???
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6 Answers
1
62I did not understand how you reached the conclusion..
I mean the consculsion would have been correct if the limit fo the integral was from 0 to 1 in the integral for B. But that is not the case!
1Yes me too since the limits of integration r different so this is not the ans.
1sorry for d silly mistake.........\int_{3}^{4}{e^{t}/t-5=\int_{0}^{1}{e^{(t+3)}/t-2}}=b
so a/b=\int_{0}^{1}{}-e^{-2-2t}
1Sry
i rechked in wolframalpha.com
it involves some Ei which mst be out of syllabus
n i found no other way to solve
though if anyone gets this plz tell