Calculus - Integrals Indefinite

1

rahul nair ·2010-02-16 09:54:52

3.1/1+x³=1/(x+1)(x²-x+1)=A/(x+1)+(Bx+c)/(x²-x+1)

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13

Avik ·2010-02-16 09:59:43

Fr 1) Have already tried by partial fraction, better approach ki talaash mein.

@rahul... thnx buddy, but i don't like this A,B,C method at all, bahut lamba pakau sort of it is ! [144]

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1

Che ·2010-02-16 10:18:49

5)

http://targetiit.com/iit-jee-forum/posts/integrate-2-13927.html

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1

rahul nair ·2010-02-16 10:27:55

@Avik,itna bhi lamba nahi hai yaar,...it'll take 30sec. max.......

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1

xYz ·2010-02-16 10:31:04

3.
will this help ?
1+x^3=(1+x)(1-x+x^2)
and then use partial fractions ;)

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13

Avik ·2010-02-16 10:34:41

k rahul, xyz... i'll do tht only then, no other rasta.

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13

Avik ·2010-02-16 10:36:34

Thnx fr the link Che.

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1

xYz ·2010-02-16 10:37:12

one more way is there it was given by kaymant sir lomg back
http://targetiit.com/iit-jee-forum/posts/for-all-u-iitians-out-there-even-my-fiitjee-sir-co-10832.html
but thats wwat i have applied

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1

Che ·2010-02-16 10:47:24

âˆ«1/(1+tanx)=âˆ«cosx/(cos+sinx)

=1/âˆš2âˆ«cosxsin(x+pi/4)dx

sybtitute
x+pi/4=t

1/âˆš2âˆ«cos(t-pi/4)sintdt

1/âˆš2âˆ«cos(t)cos pi/4-sintsinpi/4sintdt

(1/2)âˆ«cot(t)-(1/âˆš2)âˆ«sinpi/4dt

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1

xYz ·2010-02-16 10:53:58

5.
\int d\frac{\sin x-x\cos x}{x\sin x+\cos x}[6]

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