integrate 4

0 to 2pi ecosxcosx(sinx)

ans is 2pi .
I want the steps.

19 Answers

1
ankit mahapatra ·

sir its ecosx and not e*cosx.

62
Lokesh Verma ·

Ankit, I am sure some of the questions you have posted have errors..

either in the answers or the questions....

Can you tell me the source of your questions.. so that I can check them?

11
Subash ·

dint see ur posts bhaiyya

1
voldy ·

oh sry buddy . cos(Ï€-x )hi mera dimag me tha .sry my mistake.

39
Dr.House ·

yup right

11
Subash ·

i dont see what is wrong

I=0∫ecos(2Π-x)cos(2Π-x)sin(2Π-x)

I=same limits n integral of (ecosxcosx(-sinx))

I= -I

62
Lokesh Verma ·

I need to power that.. one sec i will do that..

62
Lokesh Verma ·

so what.. yes it is pwer

and cos(2pi-x) = cos x!!

11
Subash ·

ne way solution is correct no??

1
voldy ·

ankit post Q properly da . plz

39
Dr.House ·

this is an absolutely easy one dude.

1
voldy ·

nishant you've missed out a minus sign in the power .you won't get I = 0 and one request plz everybody take a bit of time and write properly no . all the powers and subscripts and all . helps ppl like me . who're duds at math . thanks guys.

62
Lokesh Verma ·

I= 0∫2pi ecosxcosx(sinx)

I = 0∫2pi ecos(2pi-x)cos(2pi-x)sin(2pi-x)

I = 0∫2pi -ecos(x)cos(x)sin(x)

Thus I=-I

Thus I=0

11
Subash ·

leave the senseless part

what about the limits

am i rite or rong

39
Dr.House ·

i muchmore senseless than u so others must correct me.!!!!!!!!!!!!!!

11
Subash ·

by taking t=cosx

and then applying limits

cos0=1=cos2Î rite

and please do correct me if im being senseless here

39
Dr.House ·

i didnt understand u subash????????

i just did it thinking it to be a indefinite integral. now we have to put limits accordingly na.

11
Subash ·

check the limits math.. dont both come out to be 1

39
Dr.House ·

let cosx=t -sinx dx=dt
therefore given integral is et t dt

solve the integral by using integration by parts

its now damn easy na dude.

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