this is a good one. according to me it would be better if u remember the solution of this which i am going to post below.
8 Answers
Dr.House
·2009-02-13 08:29:39
Dr.House
·2009-02-13 08:34:47
given integral
=2(cos9x/2cosx/2)/1-2(2cos23x/2-1) dx
now multiply and divide by cos3x/2
=2(cosx/2cos3x/2cos9x/2)/(3cos3x/2-4cos33x/2)dx
=2(cosx/2cos3x/2cos9x/2)/-cos9x/2 dx
=-2cosx/2cos3x/2 dx
= -(cos2x+cosx)dx
therefore the answer is -sin2x/2 - sinx
Dr.House
·2009-02-13 08:54:23
didi, this is one of the typical types i have seen among many that i have solved thats why...............
skygirl
·2009-02-13 09:06:36
okie... nice trick ..
can be solevd even widout knowing the trick .. :)
tho a bit two or three more steps...