INTEGRATE it

integral does not converge

yes it fails to exist...

this is actually grandi`s series in an integral form

and grandi`s series is nothing but 1-1+1-1+1.........................

I=\int_{0}^{\infty }{e^{-ax}sinx}\: dx = -\left[ \frac{e^{-ax}(asinx+cosx)}{a^2+1}\right]_{0}^{\infty }

I=\frac{1}{a^2+1}

required integral is obtained by putting a=0 which gives I = 1

sir itw a sfor students... kindly hide or remove your post...

it would help other students to think