∫dx/[(1+√x)√(x - x2)]
put √x=sinθ and proceed
Cannot fiqure it out pls give the solution
dx/(1+√x)(√x)(√(1-x))
√x=sinθdx/2√x=cosθdθ
∫2cosθdθ/(1+sinθ)(cosθ)=∫2dθ/(1+sinθ)
after subst √x=sinθ
the integral reduces to ∫ 2/(1+sinθ)
=∫ sec2 θ/2 / (1+tanθ/2)2
now put tan θ/2 =t and proceed
ok
Thx
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