Calculus - integrate

1

vector ·2009-03-16 07:04:58

take (x=3)=_t7 thn its easy

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Optimus Prime ·2009-03-16 07:08:26

what is ur answer

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1

kamalendu ghosh ·2009-03-16 07:12:33

Take {(x-2)/(x+3)}^(6/7) as t

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vector ·2009-03-16 07:14:56

7/5*(_x-2/x+3)power1/7

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33

Abhishek Priyam ·2009-03-16 07:18:10

right...

:)

good answer..

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Optimus Prime ·2009-03-16 07:19:12

u r rite richa

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vector ·2009-03-16 07:19:23

:D

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kamalendu ghosh ·2009-03-16 07:22:20

Take {(x-2)/(x+3)}^(6/7) as t {(x-2)/(x+3)}^(6/7)*(x+3)² is the denom. u will get âˆ‚t=(5)/(x+3)² there fore the integ is.. 1/5âˆ«âˆ‚t/t^(6/7)

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vector ·2009-03-16 07:24:07

no pink nishant bhaiya

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kamalendu ghosh ·2009-03-16 07:24:45

Ans:

7/5[(x-2)/(x+3)]^(1/7)

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62

Lokesh Verma ·2009-03-16 07:27:15

Awesome work richa :)

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Optimus Prime ·2009-03-16 07:27:58

what is a pinked work

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33

Abhishek Priyam ·2009-03-16 07:29:05

correct answer or expalantion or good question... or helpful posts...

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Optimus Prime ·2009-03-16 07:29:37

ok i got it

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kamalendu ghosh ·2009-03-16 07:31:46

hey... ws my method bad.???//

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