substitute √x2-x+1 =tx-1 [1]
2 Answers
Asish Mahapatra
·2009-12-04 00:09:07
rationalise it
ull get ∫x-√x2-x+1x-1
now splitting u get,
\int \frac{x}{x-1}+\frac{x^2-x+1}{(x-1)\sqrt{x^2-x+1}}dx
=\int \frac{x-1}{x-1}+1/(x-1)+\frac{x^2-x}{(x-1)\sqrt{x^2-x+1}}+\frac{1}{(x-1)\sqrt{x^2-x+1}}dx
=\int \1+1/(x-1)+\frac{x}{(x-1)\sqrt{x^2-x+1}}+\frac{1}{(x-1)\sqrt{x^2-x+1}}dx
this can be easily solved now