put x = t12
dx = 12t11dt
I=12\int [{}\frac{1}{t^{4}+t^{3}}+\frac{log(1+t^{2})}{t^{4}+t^{6}}]t^{11}dt
I=12\int [{}\frac{t^{8}}{t+1}+\frac{t^{7}log(1+t^{2})}{1+t^{2}}]dt
I_{1}=12\int {}\frac{t^{8}dt}{t+1}
I_{2}=12\int \frac{t^{7}log(1+t^{2})}{1+t^{2}}dt
log(1+t^{2})={m}, dm = \frac{2tdt}{1+t^{2}}
so,I_{2}=6\int \frac{t^{6}log(1+t^{2})2tdt}{1+t^{2}}=6\int (e^{m}-1)^{3}mdm
wich u can do further easily ,
BTW nishant sir , LAtex isnt working ....