f(θ) = ( sinθ + cos θ) 2= 1 + sin 2θ
Plz help me on this one............
∫(sinθ-cosθ)dθ/{(Sinθ+cosθ)√(sinθcosθ+sin2θcos2θ)}= cosec-1{f(θ)}+c then f(θ)=????
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UP 0 DOWN 0 0 2
Plz help me on this one............
∫(sinθ-cosθ)dθ/{(Sinθ+cosθ)√(sinθcosθ+sin2θcos2θ)}= cosec-1{f(θ)}+c then f(θ)=????