integration

AIEEE Forum › Calculus questions › integration

âˆ«[sinx + [2x/pi]] dx from pi/4 to pi/2

#Mathematics #Calculus

UP 0 DOWN 0 0 7
Post on FacebookPost anonymously?

7 Answers

262

Aditya Bhutra ·2011-10-17 07:05:19

Ans. 0

since in the given interval, 0<(2x/pi)<1 hence [2x/pi]=0
and [sinx]=0

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

Debosmit Majumder ·2011-10-17 22:37:25

i think it shud be a constant

UP 0 DOWN 0
Post on FacebookPost anonymously?

262

Aditya Bhutra ·2011-10-17 23:03:17

@debosmit - this is definite integral.

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

AVISIKTA UPADHYAY ·2011-10-18 08:31:58

could u please check again??? coz the answer is not 0. i myself got 0 as the answer but in the answer key, the answer given is not 0...

ps: could nishant sir please confirm???????

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

satyajit maurya ·2011-10-18 08:48:38

what is âˆ«0dx =???? is it 0 or a constant?

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

rishabh ·2011-10-18 08:52:57

@avisikta answer is zero and in the key also zero is given.
@satya zero.

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

AVISIKTA UPADHYAY ·2011-10-18 08:55:32

@rishab, my answer key has d wrong answer given in it...:o anyway, i am happy i have given the correct answer.

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω