integration

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âˆ«[sinx + [2x/pi]] dx from pi/4 to pi/2

#Mathematics #Calculus

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7 Answers

262

Aditya Bhutra ·2011-10-17 07:05:19

Ans. 0

since in the given interval, 0<(2x/pi)<1 hence [2x/pi]=0
and [sinx]=0

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Debosmit Majumder ·2011-10-17 22:37:25

i think it shud be a constant

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262

Aditya Bhutra ·2011-10-17 23:03:17

@debosmit - this is definite integral.

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AVISIKTA UPADHYAY ·2011-10-18 08:31:58

could u please check again??? coz the answer is not 0. i myself got 0 as the answer but in the answer key, the answer given is not 0...

ps: could nishant sir please confirm???????

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satyajit maurya ·2011-10-18 08:48:38

what is âˆ«0dx =???? is it 0 or a constant?

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rishabh ·2011-10-18 08:52:57

@avisikta answer is zero and in the key also zero is given.
@satya zero.

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AVISIKTA UPADHYAY ·2011-10-18 08:55:32

@rishab, my answer key has d wrong answer given in it...:o anyway, i am happy i have given the correct answer.

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Your Answer

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