1Write sin2x as 2sinxcosx,take cos^4x common from the denominator,We'll get the integrand as ∫2tanxsec2x/(1+tan4x) now put tanx=t
==>∫ 2tdt/(1+t4) ,put t2=u,Now it will be simple to solve
6 Answers
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1that ncert miscellaneous exercise is really worth doing.... atleast i felt so...
1yes skygirl & it was the only chapter which i felt like doing frm ncert
341or cos4x + sin4x = (cos2x+sin2x)2 - 2 sin2x cos2x
= 1 - sin22x/2 = (1+cos22x)/2
Now put cos 2x = t and integrate