Calculus - Integration

62

Lokesh Verma ·2009-01-04 08:41:06

sin⁴x+cos⁴x = (sin²x+cos²x)²-2sin²x.cos²x

= 1-(sin2x)²/2

Now change sin2x wala thing to cos 4x.

I think u can carry it from here easily :)

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Honey Arora ·2009-01-04 08:58:01

till tht i hd already done it cms 4âˆ«dx/3-cos4x .........bt i don't know hw to solve further

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62

Lokesh Verma ·2009-01-04 09:02:31

divide and multiply the num and deno by sec²2x

Sorry wrong hint at the last step..

This will be after the second step

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Honey Arora ·2009-01-04 09:22:12

i m still unable to solve this.........cn u plz post the sol.

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62

Lokesh Verma ·2009-01-04 09:31:02

sin⁴x+cos⁴x = (sin²x+cos²x)²-2sin²x.cos²x

= 1-(sin2x)²/2

Question

1/{1-(sin2x)²/2}

sec²(2x)/{sec²(2x)-tan²2x/2}

sec²(2x)/{1+tan²(2x)-tan²2x/2}

Now this is simple?

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Honey Arora ·2009-01-04 09:40:31

ys.........thx

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33

Abhishek Priyam ·2009-01-05 04:59:19

How this post is in graph of the day section..

[7]

TargetIIT Â» Forum Â» Graph of the Day Â» Integration

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Honey Arora ·2009-01-17 10:30:11

Q âˆ«₀^pi log(1+cos x)dx

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Philip Calvert ·2009-01-17 10:36:09

hey honey plz start a new topic for new question

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