just apply the rule
a∫bf(x)dx=a∫bf(a+b-x)dx
here a=-1 and b=1
and then add them
after simplifying you will get the expression as 1
so
2I=-1∫1dx=2
I=1
find the primitive of dx/(1+x3+√{1+x6}) with the limits extending from -1 to +1!!!!!!!!!!
just apply the rule
a∫bf(x)dx=a∫bf(a+b-x)dx
here a=-1 and b=1
and then add them
after simplifying you will get the expression as 1
so
2I=-1∫1dx=2
I=1