in d 1st 1 take x=tan θ...n proceed
3 Answers
msp
·2009-09-27 21:38:06
\int_{0}^{-2}{(x+1)cos(x+1)}dx=\int_{0}^{-2}{-(x+1)cos(x+1)}dx
so the value of integral is zero.
\int_{0}^{-2}{(x+1)cos(x+1)}dx=\int_{0}^{-2}{-(x+1)cos(x+1)}dx
so the value of integral is zero.