Integration

Evaluate the following:-

1)

2)

3 Answers

1
$ourav @@@ -- WILL Never give ·

in d 1st 1 take x=tan θ...n proceed

3
msp ·

\int_{0}^{-2}{(x+1)cos(x+1)}dx=\int_{0}^{-2}{-(x+1)cos(x+1)}dx

so the value of integral is zero.

1
Little Angel ·

Thankyou everyone

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