i'm getting as
1/9log!tanx!+1/6tan^2/3x+c
correct me if i'm wrong
3 Answers
Manish Shankar
·2009-04-20 07:17:53
put tanx=t3
sec2xdx=3t2dt
(1+tan2x)dx=3t2dt
(1+t6)dx=3t2dt
so the integral becomes
t.3t2dt/(1+t6)
put t2=m it becomes
(3/2)m dm/(1+m3)
now by partial fraction solve it