1the second square root is inside the first one i.e. √x^2 +2
4 Answers
1put (x+√2+x2)1/2 = t
to get (x+√2+x2)1/2 dx= 2√(x2+2) dt
√(x2+2)=(t4+2)/2t2
so we have I= t3/3 - 2/t +c
where t=(x+√2+x2)1/2
cheers!!
1√(x+√(x2+2)) = t
(x+√(x2+2))=t2
(x2+2)=t4-2xt2+x2
x=(t4-2)/2t2
x2+2 = (t8-4t4+4+8t4)/4t4
=(t8+4t4+4)/4t4
so √(x2+2)= (t4+2)/2t2
cheers!!