integration............

hi! i am new to this topic , so pls help
∫(x2tan-1x3)dx/(1 + x6)
note: do without using integration by parts

3 Answers

1
sindhu br ·

by substitution
take x3=t
now differentiate it
we get 3x2dx=dt
dx=dt/3x2
now substitute this
in eq.
so we get
1/3∫tan-1tdt/(1+t2)
pls solve & explain

1
Manas ·

is the answer (tan-1 (x3) )2 /6

1
Manas ·

then take tan-1 x as some y and then u can get it.

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