39even take \large \tan^{-1} e^{x}=t
and proceed. thats another way.
in the end u will get I= \large \int t\sec ^{2}t dt +\int t dt
3 Answers
21let ex = t
I = ∫(tan-1u)/u2
now do by parts takin (tan-1u) as da diff. functn. then its very easy
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39