The value of∫-20 [x3+3x2+3x+3+(x+1)cos(x+1)]dx is
(a)0 (b) 3 (c) 4 (d) 1
I = x4/4 + x3 + 3x2/2 + 3x
= 4
x3+3x2+3x+1+2+(x+1)cos(x+1)
-2∫0(x+1)3+(x+1)cos(x+1)+2 dx
let x+1=t
-1∫1t3+tcost+2 dt
-1∫12 dt=4
JPG, GIF or PNG only, Max size: 2MBTip: Resize your image before uploading
Sign up
Login