The value of
∫-20 [x3+3x2+3x+3+(x+1)cos(x+1)]dx is
(a)0 (b) 3 (c) 4 (d) 1
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2 Answers
Manish Shankar
·2009-10-25 07:05:47
x3+3x2+3x+1+2+(x+1)cos(x+1)
-2∫0(x+1)3+(x+1)cos(x+1)+2 dx
let x+1=t
-1∫1t3+tcost+2 dt
-1∫12 dt=4