11The 1st integral is basicaaly
\int\frac{sin2x}{\sqrt{1+sin2x}}dx=\int(sinx+cosx)dx-\int \frac{dx}{\sqrt{1+sin2x}}
For the last integral substitute the denominator as k....then it's cakewalk.
3 Answers
11
1Hi!
for the second one
take
t12=x
& solve by substitution.
if u dont get it, i will post solution