is k = 32
∫ tan-1x1+x[lower limit 0 and upper limit 1]= (pi ln2)/k
find k
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UP 0 DOWN 0 0 3
3 Answers
Tush Watts
·2009-11-01 21:58:30
Use by part,
0 ∫ 1 tan -1 x1+x = 0 ∫ 1 tan -1 x . 11+x
= tan -1 x log (1+x) - 0 ∫ 1 log (1+x) . 11 + x 2