how can xn2 come inside the bracket???
(xn2 + xn2.xn)3n
=[xn2(1+xn)]3n
=x3n(1+xn)3n
but it is given xn(1+xn)3n
∫dxxn(1+xn)3n
solve it someone... that is (1+xn) to the power 3n
\int \frac{dx}{x^{n}(1+x^{n})^{\frac{3}{n}}}
\Rightarrow \int \frac{dx}{(x^{n^{2}}+x^{n^{2}}.x^{n})^{\frac{3}{n}}}
\Rightarrow \int \frac{dx}{(x^{n^{2}}+x^{n^{2}+n})^{\frac{3}{n}}}
replace {(x^{n^{2}}+x^{n^{2}+n})^{\frac{3}{n}}} by t
@tapan..have u copy-pasted that from wolfram ????
if yes ..then i request u not to repeat that again on this site[16]........people here really work hard to crack the questions ..and it would be an insult to them and their work [2]
if no..then i take back my words [6]
how can xn2 come inside the bracket???
(xn2 + xn2.xn)3n
=[xn2(1+xn)]3n
=x3n(1+xn)3n
but it is given xn(1+xn)3n