1d answer is tooooo big..............
http://integrals.wolfram.com/index.jsp?expr=sqrt%28tan%28x%29%29&random=false
check it.......
thanks to nishu bhaiyya i got dis site hehe
6 Answers
1
62Akand..
dude all thisshould not be used ...
You are killing your brain....
This is my advice... please try to use this only as a last resort :)
even not the last one :P
1hehe i kno bhaiyya..........thts wat i thought just now........im being lazy.........................actually i tried tht but cudnt get anything out of it.........so tried tht website
1see this is what i am trying to do
tanx=t2
sec2x dx = 2t dt
dx=2tdt/1+t4
∫t . 2t / 1+t4 dt = ∫ 2t2/ t4+1
= ∫ t2+1 dt/t4+1 +∫t2-1dt /t4+1
dont know what to do after this
62great work so far..
now
\frac{t^2+1}{t^4+1}=\frac{1+1/t^2}{t^2+1/t^2}
=\frac{1+1/t^2}{(t-1/t)^2+2}
now solve :)
same for the second part