1hey yaar sky(AMRITA)........i knw that method yaar .........plz post another method naa........
13 Answers
1I knw the method of solving it by y=tanθ and then taking θ=tan-1y.......can nyone suggest another method....
1
1y u wan oder method wen u hav one dnt waste tym unnecesaarily yaar
one more thing u can do is substite log(1+x) as t
then et -1=x
then u can proceed.........
but............
.......
................................................
u end no where !!! :P
11@mani....
My brain's not working prperly now,...can you pls show intermediate steps of your working...
especially...
0∫1 (....)
=-1∫1 (....)
1i knw this method but need another method.....
y=tanθ and θ=tan-1y
dy/dx=sec2θ.dθ
so the integrand changes....changing the limits......
0∫π/4 log(1+tanθ).sec2θ.dθ/1+tan2θ
=0∫π/4 log(1+tanθ).dθ..........
Now Rest is urs....but as i told "I NEED ANOTHER METHOD"....
11good work
indeed
now i can help u further
use the property now of f(x)=f(a+b-x)
it becomes
I=0∩/4∫log (1+tan(∩/4-θ)dθ
=0∩/4∫log(2/1+tanθ)dθ
rationalize and substitute
now the question is urs[1]
1hey manipal dude i knw this method but im asking for another method.............[17][17][17]....r u not getting me......??.........[17][17][17]...
11YAAR MATRIX
SORRY 4 WASTING UR TIME YESTERDAY[2]
IT WAS REALLY AN EASY [1]
