11?????
Do by parts:
=(\tan^{-1}x)x - \frac{1}{2}\int \frac{2x}{1+x^2}dx (MY FIRST EQN USING LATEX [3])
= x\tan^{-1} x - \frac{1}{2}log(1+x^2)
: )
8 Answers
11use the product rule
take 1 as 2nd f(x)
∫tan-1x=xtan-1x-∫x/1+x2
to find 2nd integral put x = tanθ
and use the formula by reducing it to sin2x by multiplying and dividing by 2[1]
1111Sorry guys......didn't see all ur posts [2]
Took me a long time to figure out latex
1hmmmmmmm................[17][17].........[1][1]........[9][9]..........