2 Answers
Manish Shankar
·2013-08-30 03:00:39
I(m,n)=\int cos^{m}xsin(nx)dx \\=cos^{m}x(-\frac{cos(nx)}{n})-\int mcos^{n-1}x(-sinx)(\frac{-cox(nx)}{n})dx \\=-\frac{cos^{m}xcos(nx)}{n}-\frac{m}{n}\int cos^{m-1}xcos(nx)sinxdx \\=-\frac{cos^{m}xcos(nx)}{n}-\frac{m}{n}\int cos^{m-1}x[sin(nx)cosx-sin(n-1)x]dx \\=-\frac{cos^{m}xcos(nx)}{n}-\frac{m}{n}\int [cos^{m}xsin(nx)-cos^{m-1}sin(n-1)x]dx \\=-\frac{cos^{m}xcos(nx)}{n}-\frac{m}{n}[I(m,n)-I(m-1,n-1) \\I(m,n)=-\frac{cos^{m}xcos(nx)}{m+n}-\frac{m}{m+n}I(m-1,n-1)
- Soumyadeep Basu Than you, Sir.Upvote·0· Reply ·2013-08-31 00:16:21
Manish Shankar
·2013-08-30 03:44:46
or another method is
I(m,n)=∫(eix+e-ix2)m(einx-e-inx2i)
Apply by-parts taking first as u and second as v
- Soumyadeep Basu Thank you, Sir.