1take x^n out of the bracket in the Denominator
it will become x^(-n-1) / (1 + x^-n )
Which is of the form f '(x) / f(x)
3 Answers
1357you should try it yourself:
if you have tried show your steps
4Put xn + 1 = t
=> n xn-1 dx = dt
=> dx / x = dt/n(t -1)
I = INTEG [ dt / nt(t-1) ]
= 1/n ln [(t-1)/t]
Therefore , I = 1/n ln [(xn) / (xn + 1 ) ]
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