last step will answer will be -2 tan θ/2
3 Answers
UTTARA
·2009-10-02 06:37:54
Put 1-x = t2 => - dx = 2t dt
I = -2 { integ [ dt / ( √1-t2) ( 1 + √1-t2) ] }
Put t = sinθ
=> dt = cosθ dθ
I = - INTEG [ sec2θ/2 dθ ]
= - 2tan θ/2