\hspace{-16}\bf{\int \left(\frac{1}{x^6}+\frac{1}{x^8}\right)^{\frac{1}{3}}dx}$\\\\\\ $\bf{\int \frac{(1+x^{-2})^{\frac{1}{3}}}{x^2}dx}$\\\\\\ $\bf{\int x^{-2}.(1+x^{-2})^{\frac{1}{3}}dx}$
Where
Find ∫ (1x6+1x8)1/3dx
i.e integrate cubic root of (1/x6+1/x8)
\hspace{-16}\bf{\int \left(\frac{1}{x^6}+\frac{1}{x^8}\right)^{\frac{1}{3}}dx}$\\\\\\ $\bf{\int \frac{(1+x^{-2})^{\frac{1}{3}}}{x^2}dx}$\\\\\\ $\bf{\int x^{-2}.(1+x^{-2})^{\frac{1}{3}}dx}$
Where
image posting error often occurs in TIIT.
I think there is a technical problem here.