262take x = t2
∫llog xx1/2
upper limit 1
lower limit 0
form the positive side
-
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3 Answers
262I = \int_{0}^{1}{\frac{log(x)}{\sqrt{x}}}dx
let x =t2 ; dx = 2tdt
I = 4\int_{0}^{1}{{log(t)}}dt
I = 4\left<t(log(t)-1) \right>^{1} _{0}
now , \lim_{x\rightarrow 0} xlogx = 0
I = -4