is this question correct??

i m not able to prove > but i m getting x>=sinx!!!!
is the question correct??????

5 Answers

66
kaymant ·

Hint: Consider the function f(x)=x - sin x and prove that f is non decreasing for all x.

1
JOHNCENA IS BACK ·

sir that's how i tried to solve the sum!

but what i wanna say is this

f(x)=x-sin x
f'(x)=1-cos x >or=0[at points where cos x =1]
also,f(0)=0-0=0

so we conclude that function is non-decreasing[not strictly increasing]

so,x>or=sinx

so, i feel that question might be incorrect!!!

1
sid123 mishra ·

make the graph of y=x and y=Sinx.
from the graph you can clerly show that value of x is greater than Sinx.

1
lalit ·

since 0 is in open interval in domain of x we canot include 0

but at 0 x=sinx
so x>sinx is incorrect if 0 is included

but if 0 is not included then we check for a no. slightly greater then 0

lim h→0+ [sin(0+h)]=sinh=0

lim h→0+ [h] =0

so for a no. slightly greater then 0 sinx=x.
so quetion is incorrect

11
Devil ·

Mark the range....it is not [0,∞).

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