331/2k
[3]
limn→∞ (n!/(nk)n)1/n
please do solve this even if it seems simple
i don't think answer should be 1/(2k) but if you get this somehow it'll be very interesting
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39 Answers
11so is it non integrable in the given limits
because it is discontinuous
21INTERESTIN.....
BUT I THJNK THE BOUNDIN VALUES R NTO 2 B COUNTED.....
SOLVE THIIS IT'LL B CLEARER...
0∫2π [sin(x)] ∂x
wer [.] denotes gr8est int.
{HINT : FOR WAT RANGE WILL U INTEGRATE FOR [sin(x)] = 1 ???? [7] }
21dont think much....
ther is no value/range for which u will b integratin [sinx] = 1;
thats y i said ignore the limits though v sub them while solving general int. sums.....
coz in 0 to π/2 [sijnx] = 0;
its jus at dat 1 infinitesimal pt that [sinx] = 1;
therfor v do not find any range for [sinx]=1;
HOPE U GOT MA PT
