find the limit of (e^{x}-{x}-1)/{x}^2 when x→[a] where {.} denotes fractional part and [.] denotes integral part
-
UP 0 DOWN 0 0 2
2 Answers
iitimcomin
·2009-07-19 08:14:20
as we approach the integer frm lh side ... we get .. {x} --> 1
else it tendz to zero ...
so lhl we get as e-1-1/2 ...... rhl as 1/2 ...... lt dosnt exist ....:((
Lokesh Verma
·2009-07-19 21:03:30
(e{x}-{x}-1){x}^2
Use expansion...
{x}->1 when we take x->[a] from the LHS
so the expression's LHL will be e-2
RHL will be found by LH rule... and will be 1/2
So the limit does not exist..