0 (use LH)
or am i missing something here
yes ans=0,
can you explain me.....
bcz when n-->∞
it is in \propto /\propto
(i have a confusion )...
it is ∞/∞
So use LH
we get lim(n→∞) 110n+1ln10
which is 0/∞ = 0
what is (LH)
mujhai samaz mai nahi aa raha hai....
(so can u plz explain 1 more time)....
L-Hospital rule
If u have a limit of the form 0/0 or ±∞/±∞
then to evaluate the limit you differentiate the num wrt the variable and the denominator wrt the variable and then evaluate the limit...
for an example see what i have done abv