I THINK there will be 2 cases, n may be odd or even..
Find the limiting value of { (√2 + 1)n} x (-1)[(√2 + 1)n] where n →∞ {} →fractional part [.] →G.I.F.
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5 Answers
Vivek @ Born this Way
·2012-02-03 06:03:42
It is indeed -1.
Whatever may be the case (ie.., Odd or Even), it will be -1 . [ Only if n → ∞ and n ε Natural Number ]
I had made a post about this on Aops!