LIMITASSS

THE FUNDA TO BE USED HERE IS

WHEN x→∞ THEN [x] CAN BE TAKEN AS x
AND IN THE DENOMINATOR USE THE EXPANSION OF e^x = 1+x/1!+x²/2! + x³/3!........
CUT IN THE NUMERATOR AND THE DENOMINATOR TO GET UR ANSWER

nahi pata ans

a small correction.... we get 1/e^[x] =0. isn it???????

@sky we just cant substitue directly n as zero as d ans can have n term in limit questions

nahin yaar lim _x->∞ 2/e^[x] = 0

but nothing is told about 'n' //

so .............. !!