Using Sandwhich theorem ----->0
- Himanshu Giria and u may apply L Hospuital's Rule also ...
Upvote·0· Reply ·2014-05-18 19:48:19
- Anindita Roy Plz show the working
Using Sandwhich theorem ----->0
x-1<[x]<=x
as x ->(infinity) [x]=x as x-1->
x and x->x
... lim = ((d log x /dx) / ( dx/dx )) = 1/x/1/1 =1/x =0...