limits!!

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#Mathematics #Calculus

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4 Answers

1357

Manish Shankar ·2011-02-20 21:39:10

c has to be 1/5....

the questions needs you to take x common..

after wjocj upi wo;; get 7/5 as the limiting value..

You need to realize that x^a-x^b (lim x going to infinity) is zero only if a=b

when both a and b are greater than zero...

Here that is the first step...

Then use exapansion or binomial theorem or even rationalization to get the limit..

can you try using this hint?

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71

Vivek @ Born this Way ·2011-02-21 03:43:45

take x common..

How do we do that sir?

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DJ ·2011-02-21 04:25:53

Ans is 1... wats d ans???

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23

qwerty ·2011-02-22 02:26:00

it will be easier to understand if we put y = 1/x

then we have

lim y->0^- (1y⁵ + 7y⁴+2)^c - 1y

now clearly c = 1/5 so that the outside term 1/y gets cancelled somehow so that limit exists , and then the rest follows

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Basic Integral Calculus Operators Symbols Matrix Cases

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