Am getting c) 1/3.
As "x" tends to Zero in each case, look at seires expansions an terms inside brackets in each case.
In the numerator, it'll be smthing like this evntually-
Lim(x→0) -(a)x6-(b)x8+x5+ Higher pwrs7x7+x6+3x5+ Higher pwrs
(a and b are constants)
So, Taking out "x5" common and cancelling, limit comes out to be 1/3.
Too unconventional a method i know, but still.. :P