limits!!

Am getting c) 1/3.

As "x" tends to Zero in each case, look at seires expansions an terms inside brackets in each case.

In the numerator, it'll be smthing like this evntually-

Lim(x→0) -(a)x⁶-(b)x⁸+x⁵+ Higher pwrs7x⁷+x⁶+3x⁵+ Higher pwrs

(a and b are constants)
So, Taking out "x⁵" common and cancelling, limit comes out to be 1/3.

Too unconventional a method i know, but still.. :P

DIVIDE THE NUMERATOR AND DENOMINATOR BY X⁵....NOW CLEARLY LIMIT IS 1/3