limits!!

3 Answers

1
_€nigma_ ·

Am getting c) 1/3.

As "x" tends to Zero in each case, look at seires expansions an terms inside brackets in each case.

In the numerator, it'll be smthing like this evntually-

Lim(x→0) -(a)x6-(b)x8+x5+ Higher pwrs7x7+x6+3x5+ Higher pwrs

(a and b are constants)
So, Taking out "x5" common and cancelling, limit comes out to be 1/3.

Too unconventional a method i know, but still.. :P

1
kunl ·

DIVIDE THE NUMERATOR AND DENOMINATOR BY X5....NOW CLEARLY LIMIT IS 1/3

1
pavancm8 cm ·

1/3

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