1its will be ∞.
Write cot x = 1/(tan x), take LCM & then apply L'Hospital's Rule.....if u want the full solution to convince urself.....well it looks just by seeing the q that it is ∞ !
11 Answers
106well write sinx as x
ull get it as (1-xcosx)/x2
applying the limits it is 1/0+ = +∞
21i guess ans is 0....
(1-x2cotx)/x2
now use exp of cot x
and then apply l hospital
1106yes virang when x--> 0 sinx/x --> 1 so sinx --> x
so ur allowed to rite that... (but in some cases where u have sinx - tanx) dont use it... tho..
21ok u can directly use l hopital der
or may use this xcotx=1 -x3/3 + x4/45...............
and then apply l hospital
1LHL = (∞ + ∞), which is always +ve.
But, RHL = (∞ - ∞), which can be +ve or -ve!
Hence, the limit cant exist!! :)